Asked by Unknown.
Help?
I Kind of understand this , but still I am stuck.
1. (2+4i)/3-i
2. 3√-50 + -72
3.(-4+√-15)^2
4.-4+√-20
5.7√-2(-4√-3)
I Kind of understand this , but still I am stuck.
1. (2+4i)/3-i
2. 3√-50 + -72
3.(-4+√-15)^2
4.-4+√-20
5.7√-2(-4√-3)
Answers
Answered by
Steve
we kind of don't know where you get stuck. Show us what you got, and we can help you work it the rest of the way.
Answered by
Unknown.
1. I got 6+3/10
but i don't believe that's the correct answer.
2. i got √21.21+√-8.49
3. i got 34+14√10i
4. i got -1+√5i
but i don't believe that's the correct answer.
2. i got √21.21+√-8.49
3. i got 34+14√10i
4. i got -1+√5i
Answered by
Steve
#1: (2+4i)/(3-i)
= (2+4i)(3+i) / (3-i)(3+i)
= (6 + 12i + 2i + 4i^2) / (3^2 - i^2)
= (6 + 14i - 4) / (9+1)
= (2+14i)/10
= 1/5 + 7/5 i
#2: 3√-50 + -72
3√50 i - 72
3*5√2 i - 72
-72 + 15√2 i
in this kind of exercise, there's no call to approximate √ values with decimals. The √ is exact; the decimals are only an approximation.
#3: (-4+√-15)^2
= (-4 + √15 i)^2
= (-4)^2 + 2(-4)(√15 i) + (√15 i)^2
= 16 - 8√15 i - 15
= 1 - 8√15 i
#4: -4+√-20
= -4 + √20 i
= -4 + 2√5 i
#5: 7√-2(-4√-3)
= 7(√2 i)(-4)(√3 i)
= -28 √6 i^2
= 28√6
Does that help? Just take these things step by step, keeping track of the i's and signs.
= (2+4i)(3+i) / (3-i)(3+i)
= (6 + 12i + 2i + 4i^2) / (3^2 - i^2)
= (6 + 14i - 4) / (9+1)
= (2+14i)/10
= 1/5 + 7/5 i
#2: 3√-50 + -72
3√50 i - 72
3*5√2 i - 72
-72 + 15√2 i
in this kind of exercise, there's no call to approximate √ values with decimals. The √ is exact; the decimals are only an approximation.
#3: (-4+√-15)^2
= (-4 + √15 i)^2
= (-4)^2 + 2(-4)(√15 i) + (√15 i)^2
= 16 - 8√15 i - 15
= 1 - 8√15 i
#4: -4+√-20
= -4 + √20 i
= -4 + 2√5 i
#5: 7√-2(-4√-3)
= 7(√2 i)(-4)(√3 i)
= -28 √6 i^2
= 28√6
Does that help? Just take these things step by step, keeping track of the i's and signs.
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