Help?
I Kind of understand this , but still I am stuck.
1. (2+4i)/3-i
2. 3√-50 + -72
3.(-4+√-15)^2
4.-4+√-20
5.7√-2(-4√-3)
3 answers
we kind of don't know where you get stuck. Show us what you got, and we can help you work it the rest of the way.
1. I got 6+3/10
but i don't believe that's the correct answer.
2. i got √21.21+√-8.49
3. i got 34+14√10i
4. i got -1+√5i
but i don't believe that's the correct answer.
2. i got √21.21+√-8.49
3. i got 34+14√10i
4. i got -1+√5i
#1: (2+4i)/(3-i)
= (2+4i)(3+i) / (3-i)(3+i)
= (6 + 12i + 2i + 4i^2) / (3^2 - i^2)
= (6 + 14i - 4) / (9+1)
= (2+14i)/10
= 1/5 + 7/5 i
#2: 3√-50 + -72
3√50 i - 72
3*5√2 i - 72
-72 + 15√2 i
in this kind of exercise, there's no call to approximate √ values with decimals. The √ is exact; the decimals are only an approximation.
#3: (-4+√-15)^2
= (-4 + √15 i)^2
= (-4)^2 + 2(-4)(√15 i) + (√15 i)^2
= 16 - 8√15 i - 15
= 1 - 8√15 i
#4: -4+√-20
= -4 + √20 i
= -4 + 2√5 i
#5: 7√-2(-4√-3)
= 7(√2 i)(-4)(√3 i)
= -28 √6 i^2
= 28√6
Does that help? Just take these things step by step, keeping track of the i's and signs.
= (2+4i)(3+i) / (3-i)(3+i)
= (6 + 12i + 2i + 4i^2) / (3^2 - i^2)
= (6 + 14i - 4) / (9+1)
= (2+14i)/10
= 1/5 + 7/5 i
#2: 3√-50 + -72
3√50 i - 72
3*5√2 i - 72
-72 + 15√2 i
in this kind of exercise, there's no call to approximate √ values with decimals. The √ is exact; the decimals are only an approximation.
#3: (-4+√-15)^2
= (-4 + √15 i)^2
= (-4)^2 + 2(-4)(√15 i) + (√15 i)^2
= 16 - 8√15 i - 15
= 1 - 8√15 i
#4: -4+√-20
= -4 + √20 i
= -4 + 2√5 i
#5: 7√-2(-4√-3)
= 7(√2 i)(-4)(√3 i)
= -28 √6 i^2
= 28√6
Does that help? Just take these things step by step, keeping track of the i's and signs.