Ask a New Question

Asked by deel

how to find the following limit :

lim lnx/lgx
x->infinity

13 years ago

Answers

Answered by Steve
If lg(x) = log<sub>2</sub>x, then since

lgx = lnx/ln2,

lnx/lgx = ln2 for all x.
13 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not... Find the limit Limit as h approaches 0 of : SqRt(4+h)-2 ____________ h by rela... Find the following limit where f(x) = 4x^2 − 3x. limit-->(f(x+ delta x)-f(x))/(delta x) delt... How do you find the limit of: 1(1 - (1/k))/2! as k increased with no bound? I know the answer... how do you find the limit at infinity of: lim(x->infinity) (x+2)/sqrt(64 x^2+1) Do you first c... how do i find the limit of this? (This symbol:-> is an arrow) lim of x-> 0 sin^2x/x can som... Find the limit. lim h → 0 square root (49 + h) − 7 / h Note: Only 49 +h are under square... Find the limit. lim x-->1 (x^3)-1/((5x^2)+2x-7) Please show steps. 1) find the indicated limit, if it exist? a) lim x->-2 (x^2 -9)/(x^2+x-2) b) lim x -> -∞ √(ax^... f(x)=x/x^2 – x find limit??? Pleaseee thnks
Submit Your Answer

Question

how to find the following limit :

lim lnx/lgx
x->infinity

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use