Question

A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $11000 dollars. How much did he invest at each rate?

Answer 1

amount in lower rate --- 2x dollar
amount at higher rate --- x dollars

.06(2x) + .10x = 11000
.12x + .10x = 11000
.22x = 11000
x = 11000/.22 = 50000

so 50000 invested at 10% and
100000 invested at 6%