Asked by Unknown
HELP?!
Equations With Rational Expressions;
1. 5/2y+6 + 1/y-2 = 3/y+3
2. 5/a-5 - 1 = a/a-5
3. 2/x^2-x-12 - 6/x+4 = 2/x-3
4. 65-n/n = 4 + 5/n
5. a/ a-2 + 2/3 = 2/a-2
6. x-1/3 + x+2/4 =1/6
7. 5/3x - 1/9 = 1/x
8. 3/3x-2 = 4/2x+1
9. 3/x+3 - 1/x-2 = 5/2x+6
Equations With Rational Expressions;
1. 5/2y+6 + 1/y-2 = 3/y+3
2. 5/a-5 - 1 = a/a-5
3. 2/x^2-x-12 - 6/x+4 = 2/x-3
4. 65-n/n = 4 + 5/n
5. a/ a-2 + 2/3 = 2/a-2
6. x-1/3 + x+2/4 =1/6
7. 5/3x - 1/9 = 1/x
8. 3/3x-2 = 4/2x+1
9. 3/x+3 - 1/x-2 = 5/2x+6
Answers
Answered by
Reiny
The way you typed your equations makes them much too ambiguous.
e.g. #2
is it 5/a - 5 - 1 = a/a - 5 the way your typed it, or is it
5/(a-5) - 1 = a/(a-5)
I supect it is the latter.
so multiply each term by the LCD, which would be a-5 to get
5 - 1(a-5) = a
5 - a + 5 = a
-2a =-10
a = -5
clarify the others before I proceed
Try these yourself, remember by multiplying by the LCD, all fractions will disappear.
e.g. #2
is it 5/a - 5 - 1 = a/a - 5 the way your typed it, or is it
5/(a-5) - 1 = a/(a-5)
I supect it is the latter.
so multiply each term by the LCD, which would be a-5 to get
5 - 1(a-5) = a
5 - a + 5 = a
-2a =-10
a = -5
clarify the others before I proceed
Try these yourself, remember by multiplying by the LCD, all fractions will disappear.
Answered by
Unknown.
1. 5/(2y+6) + 1/(y-2) = 3/(y+3)
2. 5/(a-5) - 1 = a/(a-5)
3. 2/(x^2)-x-12 - 6/(x+4) = 2/(x-3)
4. 65-n/(n) = 4 + 5/(n)
5. a/ (a-2) + 2/(3) = 2/(a-2)
6. x-1/(3) + x+2/(4) =1/(6)
7. 5/(3x) - 1/(9) = 1/(x)
8. 3/(3x-2) = 4/(2x+1)
9. 3/(x+3) - 1/(x-2) = 5/(2x+6)
* " / " That Is Suppose to be a fraction line.
2. 5/(a-5) - 1 = a/(a-5)
3. 2/(x^2)-x-12 - 6/(x+4) = 2/(x-3)
4. 65-n/(n) = 4 + 5/(n)
5. a/ (a-2) + 2/(3) = 2/(a-2)
6. x-1/(3) + x+2/(4) =1/(6)
7. 5/(3x) - 1/(9) = 1/(x)
8. 3/(3x-2) = 4/(2x+1)
9. 3/(x+3) - 1/(x-2) = 5/(2x+6)
* " / " That Is Suppose to be a fraction line.
Answered by
Reiny
some are still ambigious,
e.g. #4 and #6
is #6 (x-1)/3 + (x+2)/4 = 1/6 ???
there is no need to place brackets around the 3 or the 4, but they are needed at the top.
(x-1)/3 + (x+2)/4 = 1/6
multiply each term by 12, which is the LCD for 3,4, and 6
4(x-1) + 3(x+2) = 2
4x-4+3x+6=2
7x = 0
x = 0
try some of the others, let me know what you got
e.g. #4 and #6
is #6 (x-1)/3 + (x+2)/4 = 1/6 ???
there is no need to place brackets around the 3 or the 4, but they are needed at the top.
(x-1)/3 + (x+2)/4 = 1/6
multiply each term by 12, which is the LCD for 3,4, and 6
4(x-1) + 3(x+2) = 2
4x-4+3x+6=2
7x = 0
x = 0
try some of the others, let me know what you got
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.