Question

a particle is dropped under gravity from rest from a height and it travels a distane of 9h/25 in the last second. Calculate the height h?

Answer 1

Let the total fall time be t.

h = (g/2) t^2
(16/25)h = (g/2)(t-1)^2]

16/25 = [(t-1)/t]^2
Take the positive square root of both sides.
4/5 = (t-1)/t
t = 5
h = (g/2)*25 = 122.5 meters

Answer 2

Thanks