Asked by economyst
1) No, 8.0 is the correct answer.
2) a strange and unlikely probability distribution. But lets go with the stated parameters. It states that ZERO percent of the population loses less than 6 lbs OR more than 12 lbs, but exactly evenly distributed between 6 and 12. The denominator for your probability questions will be 6. Soooooo.
1) P(10 or more) = 2/6 = .333
2) P(8 to 11) = 3/6 = .500
3) P(9 to 12) = 3/6 = .500
Find the mean, u, for the binomial distribution whch has the state vlaues of n and p. Round answer to the nearest tenth.
n = 40; p = .2
is u = 80 correct
Assume that live weight loss for the first month of a diet program varies between 6 pounds and 12 pounds and is spread evenly over the rangeof possibilities so that there is a uniform distribution. First the probability of the given range of pounds lost.
1. more than 10 pounds
2. between 8 pounds and 11 pounds
3. between 9 pounds and 12 pounds
can anyone please help. I don't know how to do this
2) a strange and unlikely probability distribution. But lets go with the stated parameters. It states that ZERO percent of the population loses less than 6 lbs OR more than 12 lbs, but exactly evenly distributed between 6 and 12. The denominator for your probability questions will be 6. Soooooo.
1) P(10 or more) = 2/6 = .333
2) P(8 to 11) = 3/6 = .500
3) P(9 to 12) = 3/6 = .500
Find the mean, u, for the binomial distribution whch has the state vlaues of n and p. Round answer to the nearest tenth.
n = 40; p = .2
is u = 80 correct
Assume that live weight loss for the first month of a diet program varies between 6 pounds and 12 pounds and is spread evenly over the rangeof possibilities so that there is a uniform distribution. First the probability of the given range of pounds lost.
1. more than 10 pounds
2. between 8 pounds and 11 pounds
3. between 9 pounds and 12 pounds
can anyone please help. I don't know how to do this