Asked by skye
use power reducing identities to prove the identity
sin^4x=1/8(3-4cos2x+cos4x)
cos^3x=(1/2cosx) (1+cos2x)
thanks :)
sin^4x=1/8(3-4cos2x+cos4x)
cos^3x=(1/2cosx) (1+cos2x)
thanks :)
Answers
Answered by
Steve
cos 2x = 2cos^2 x - 1
so, 1/2 cos x (1+2cos^2 x - 1) = cos^3 x
cos 4x = 1 - 2sin^2 2x
= 1 - 8sin^2 x cos^2 x
= 1 - 8sin^2 x (1 - sin^2 x)
= 1 - 8sin^2 x + 8 sin^4 x
cos 2x = 1 - 2sin^2 x
4cos 2x = 4 - 8sin^2 x
1/8(3-4cos2x+cos4x)
= 1/8(3 - 4 + 8sin^2 x + 1 - 8sin^2 x + 8 sin^4 x)
= 1/8(8sin^4 x)
= sin^4 x
so, 1/2 cos x (1+2cos^2 x - 1) = cos^3 x
cos 4x = 1 - 2sin^2 2x
= 1 - 8sin^2 x cos^2 x
= 1 - 8sin^2 x (1 - sin^2 x)
= 1 - 8sin^2 x + 8 sin^4 x
cos 2x = 1 - 2sin^2 x
4cos 2x = 4 - 8sin^2 x
1/8(3-4cos2x+cos4x)
= 1/8(3 - 4 + 8sin^2 x + 1 - 8sin^2 x + 8 sin^4 x)
= 1/8(8sin^4 x)
= sin^4 x
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.