Asked by Patsy
A compound of molecular weight 70.1 has the following composition: Carbon 85.63% and hydrogen 14.37%. What is the empirical formula? What is the molecular formula?
Answers
Answered by
Steve
70.1*.8563/12 = 5.00 moles C
70.1*.1437/1 = 10.07 moles H
empirical CH2 has mol wt 14
70.1/14 = 5, so
molecular formula is C5H10
70.1*.1437/1 = 10.07 moles H
empirical CH2 has mol wt 14
70.1/14 = 5, so
molecular formula is C5H10
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