A car is travelling at 30.0 mi/h (13.41 m/s) on a level road where the coefficient of static friction between its tires and the road is 0.70. Find the minimum turning radius of the car.

Answer 1

Since the road is level (unbanked), the maximum friction force M*g*Us must equal the centripetal force M V^2/R, at minimum turning radius.

R = V^2/(g*Us) = (13.41)^2/(9.8*0.70)
= 26.2 meters