Asked by Amelia
(6y)/(y^2+y-72 divided by (y^6)/(8-y).
Answers
Answered by
drwls
(6y)/(y^2+y-72) = 6y/[(y+9)(y-8)]
Multiply that by (8-y)y^6
6 y^7*(-1)/(y+9)
= -6y^7/(y+9)
Multiply that by (8-y)y^6
6 y^7*(-1)/(y+9)
= -6y^7/(y+9)
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