Find k, given that (2,k) is equidistant from (3,7) and (9,1).

Question

The answer is : k=0

How do I solve this problem?

Answer 1

The slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.

Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.

So, we want the line with slope=1, through (6,4), the midpoint of the segment.

y-4 = 1(x-6)
Now, we plug in (2,k) to get
k-4 = 2-6
k = 0

Answer 2

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Answer 3

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