Asked by sarah

find if the series is convergent and what it sums to

the sum from k=3 to infinity of (k+1)^2/((k-1)(K-2))

I'm not sure how to start

Answers

Answered by Count Iblis
How does (k+1)^2/((k-1)(K-2)) behave for large k?
Answered by sarah
isn't it infinity/infinity, which is undefined?
Answered by Count Iblis
It's infinity/infinity but you can compute the limit, which is finite. Som try to compiute the limit and show that it is nonzero. Then you say that because the limit is not zero the series cannot converge.

Note that even if the limit were zero, that would still not guarantee convergence of the series. The terms have to approach zero fast enough...
Answered by sarah
how would you compute the limit?
when i do it on my calculator i find the limit is undefined...what does that say for the sum?
Answered by Count Iblis
(k+1)^2/((k-1)(K-2)) =

[k^2 + 2 k + 1]/[k^2 - 3 k + 2] =

[1 + 2/k + 1/k^2]/[1 - 3/k + 2/k^2]

Can you see what happens if k --> infinity?
Answered by sarah
is it approaching 0?
Answered by Count Iblis
[1 + 2/k + 1/k^2]/[1 - 3/k + 2/k^2]

Numerator is

A(k) = 1 + 2/k + 1/k^2

Denominator is:

B(k) = 1 - 3/k + 2/k^2

What are the limits of A(k) and B(k) for k ---> infinity?
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