Asked by sarah
TRUE OR FALSE
1. if the lim as n->infinity of a(sub n)=0, then the sum from n=1 to infinity of a(sub n) converges
i said this was true because I know that if a (sub n) does NOT=0, it diverges
2. if the sum from n=1 to infinity of a(sub n) converges and a(sub n) does not =0, then the sun from n=1 to infinity of 1/(a(sub n)) diverges.
?????
1. if the lim as n->infinity of a(sub n)=0, then the sum from n=1 to infinity of a(sub n) converges
i said this was true because I know that if a (sub n) does NOT=0, it diverges
2. if the sum from n=1 to infinity of a(sub n) converges and a(sub n) does not =0, then the sun from n=1 to infinity of 1/(a(sub n)) diverges.
?????
Answers
Answered by
Count Iblis
1) is false. Counterexample: a_n = 1/n
Try to prove that sum from n=1 to infinity of 1/n is divergent.
"i said this was true because I know that if a (sub n) does NOT=0, it diverges"
Which is logically equivalent to:
Not divergent implies a_n ---> 0.
Of course, a convergent series must be such that a_n --->0. But the reverse is not true. So, the condition a_n ---> 0 is necessary but not sufficient for convergence.
Try to prove that sum from n=1 to infinity of 1/n is divergent.
"i said this was true because I know that if a (sub n) does NOT=0, it diverges"
Which is logically equivalent to:
Not divergent implies a_n ---> 0.
Of course, a convergent series must be such that a_n --->0. But the reverse is not true. So, the condition a_n ---> 0 is necessary but not sufficient for convergence.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.