Question
The perimeter of a soccer field is 280yd. The width is 5yd more than half the length. Can you help me with the formula to solve this problem?
Answers
Ms. Sue
P = 2L + 2W
280 = 2L + 2(0.5L + 5)
280 = 2L + L + 10
280 = 3L + 10
270 = 3L
90 = L
280 = 2L + 2(0.5L + 5)
280 = 2L + L + 10
280 = 3L + 10
270 = 3L
90 = L