Asked by Emmett
Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.)
4x4 + 15x2 − 4 = 0
4x4 + 15x2 − 4 = 0
Answers
Answered by
MathMate
Let y=x²
the equation can then be written as
4y²+15y-4=0
Solve for y using the quadratic formula (i.e. find y1 and y2).
Since y=x², then
x=±√(y1) or ±√(y2)
giving a total of 4 solutions.
the equation can then be written as
4y²+15y-4=0
Solve for y using the quadratic formula (i.e. find y1 and y2).
Since y=x², then
x=±√(y1) or ±√(y2)
giving a total of 4 solutions.
Answered by
Demps
Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.)
4^4 + 15^2 − 4 = 0
4^4 + 15^2 − 4 = 0
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