Asked by Josh G.

A Princeton prof. (mass = 70.0 kg), surprised by the large stopping force he calculates for jumping flat footed from a height of 0.12 m, decides to try the experiment. Calculate he deceleration (in g's) if he stops in a distance of 0.36 cm. (Do not try this. You could easily break an ankle!)

Answers

Answered by drwls
V at impact = sqrt (2 g H) = 1.53 m/s

If a is the deceleration after impact,
V = sqrt (2 a d), where d = 3.6*10^-3 m
a = V^2/(2 d) = 327 m/s^2
(33 g's)

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