Asked by Josh G.
A Princeton prof. (mass = 70.0 kg), surprised by the large stopping force he calculates for jumping flat footed from a height of 0.12 m, decides to try the experiment. Calculate he deceleration (in g's) if he stops in a distance of 0.36 cm. (Do not try this. You could easily break an ankle!)
Answers
Answered by
drwls
V at impact = sqrt (2 g H) = 1.53 m/s
If a is the deceleration after impact,
V = sqrt (2 a d), where d = 3.6*10^-3 m
a = V^2/(2 d) = 327 m/s^2
(33 g's)
If a is the deceleration after impact,
V = sqrt (2 a d), where d = 3.6*10^-3 m
a = V^2/(2 d) = 327 m/s^2
(33 g's)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.