Asked by Rajan
A flywheel has an angular speed of 1200 rev/min when its motor is turned off. The wheel attains constant decelerations of 1.5 rad/s2 due to friction in its bearing. Determine the time required for the wheel to come to rest and the number of revolutions the wheel makes before it comes to rest
Answers
Answered by
Elena
2π•f(fin)= 2π•f(init)-εt
f(fin)=0, f(init) = 1200 rev/min =20 rev/s.
2π•f(init)=εt
t=2π•f(init)/ ε= 2π•20/1.5=83.8 s.
2π•N= 2π•f(init) •t - εt²/2.
N= f(init) •t - εt²/4π=
=20•83.8 – 1.5•(83.8)²/4•π =
= 838 rev.
f(fin)=0, f(init) = 1200 rev/min =20 rev/s.
2π•f(init)=εt
t=2π•f(init)/ ε= 2π•20/1.5=83.8 s.
2π•N= 2π•f(init) •t - εt²/2.
N= f(init) •t - εt²/4π=
=20•83.8 – 1.5•(83.8)²/4•π =
= 838 rev.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.