dS is + (i.e., >0) when S products is greater than S for reactants.
A has 3 mols gas on the left and 1 on the right; therefore, dS decreases.
Remember S increases from solids to liquids to gases. Therefore, A and B can't be right.
For which reaction is delta Ssys > 0?
A) CH4(g) + 2 O2(g) �¨ CO2(g) + 2 H2O(l)
B) NH3(g) + HCl(g) �¨ NH4Cl(s)
C) 2 NH4NO3(s) �¨ 2 N2(g) + O2(g) + 4 H2O(g)
D) HCl(aq) + NaOH(aq) �¨ NaCl(aq) + H2O(l)
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