Asked by Jon
Exactly how many digits are in 302627325(2^5300001+1)
Answers
Answered by
Steve
we can ignore the "+1" since it adds a minuscule amount to the total.
log302627325(2^5300001)
= log 302627325 + 5300001 log2
= 1595467.76
so, I'd say there are 1,595,468 digits
log302627325(2^5300001)
= log 302627325 + 5300001 log2
= 1595467.76
so, I'd say there are 1,595,468 digits
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