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In a normal distribution with the mean being 500 and the standard deviation being 100, what raw score separates the top 40% of...Asked by Jessica
In a normal distribution with the mean being 500 and the standard deviation being 100, what raw score separates the top 40% of a distribution from the rest?
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Answered by
MathGuru
Find the z-score using a z-table that represents the top 40%. Then use z-score formula to find x.
z = (x - mean)/sd
mean = 500
sd = 100
I hope this will help get you started.
z = (x - mean)/sd
mean = 500
sd = 100
I hope this will help get you started.
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