Asked by Jessica
Drivers pay an average of (mean $690) per year for automobile insurance the distribution of insurance payments is approximately normal with a standard deviation of 110 dollars. What proportion of drivers pay more than 100 dollars per year for insurance?
Answers
Answered by
catherine
how to get answer to geometric mean problem? data: 25.4, 9, 16, 4.25, 8.11, 19?
Answered by
MathMate
Check for typo in your post. If there are no typos, here's how you would proceed.
Standardize:
P(X>100)
=1-P(X≤100)
=1-P(Z≤(100-690)/110)
=1-P(Z≤-5.36)
Look up a probability table for
P(Z≤-5.36) and calculate the answer accordingly.
Standardize:
P(X>100)
=1-P(X≤100)
=1-P(Z≤(100-690)/110)
=1-P(Z≤-5.36)
Look up a probability table for
P(Z≤-5.36) and calculate the answer accordingly.
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