Asked by Alex
A baseball teams ace pitcher throws fast balls at a velocity of 160kmh, the balls are released at a height of 1.6m from the ground, given that the distance between pitcher and plate is 18.4m how far has the ball dropped when it passes over the plate?
Answers
Answered by
drwls
First convert 160 km/h to 44.4 m/s.
Assuming that the initial velocity of the throw is horizontal (which may not be true in practice) the ball drops (1/2) g t^2, where t is the time of flight to home plate, 18.4/44.4 = 0.41 s.
g is the acceleration of gravity, as you know.
You will not need to use the 1.6 meter number to get the answer.
Assuming that the initial velocity of the throw is horizontal (which may not be true in practice) the ball drops (1/2) g t^2, where t is the time of flight to home plate, 18.4/44.4 = 0.41 s.
g is the acceleration of gravity, as you know.
You will not need to use the 1.6 meter number to get the answer.
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