Asked by Tony

Show the solutions of

1. If a = 4, b = 3, and A = 36o.

2. If a = 3, b = 4, and A = 48.59o


Finding a "solution" means solving for all missing sides and angle measures in each triangle.)
Answered by Henry
Use Law of Sines.

1. sinB/b = sinA/a
sinB/3 = sin36/4
Multiply both sides by 3:
sinB = 3*sin36/4 = 0.44084
B = 26.16 Deg.

C = 180 -36 - 26.16 = 117.8 Deg.

c/sinC = a/sinA
c/sin117.8 = 4/sin36
Multiply both sides by sin117.8:
c = 4*sin117.8/sin36 = 6.

2. Same procedure as #1.

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