Asked by Beth
How many half-lives are required for the number of radioactive nuclei to decrease to 1/10^4 of the initial number?
Answers
Answered by
drwls
Let N be the number of half-lives.
(1/2)^N = 10^-4
N log(0.5) = log(10^-4)
-0.30103 N = -4
N = 13.29 half-lives
(1/2)^N = 10^-4
N log(0.5) = log(10^-4)
-0.30103 N = -4
N = 13.29 half-lives
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