Asked by Beth
Determine the activity of 1.11 g of 88Ra226 (a) in disintegrations per second (Bq) (b) and in Curies (Ci). The half-life is 1600 yr (1 yr = 3.156 x 10^7 s). 1 Ci is equal to 3.7 x 10^10 Bq.
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Solve for k.
# atoms = N<sub>o</sub> = (1.11/88)*6.02E23) = ?N<sub>o</sub>. Then
R<sub>o</sub> = kN<sub>o</sub> = ? disintegrations per year. Convert to dps and Ci.
Solve for k.
# atoms = N<sub>o</sub> = (1.11/88)*6.02E23) = ?N<sub>o</sub>. Then
R<sub>o</sub> = kN<sub>o</sub> = ? disintegrations per year. Convert to dps and Ci.
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