Asked by Zac
Assume the Earth is a perfect sphere of radius 6,400 kilometers. Find the weight of a 75.0 kg
person at the North pole. Find the weight of this same person at the equator. (You don't need to use
Newton's Law of Gravitation but you do need to analyze the radial/centripetal force.)
person at the North pole. Find the weight of this same person at the equator. (You don't need to use
Newton's Law of Gravitation but you do need to analyze the radial/centripetal force.)
Answers
Answered by
Elena
Weight(pole) = mg,
Weight (equator) =mg - F(centripetal)=mg - mv²/R
Weight (equator) =mg - F(centripetal)=mg - mv²/R
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.