Question
Assume the Earth is a perfect sphere of radius 6,400 kilometers. Find the weight of a 75.0 kg
person at the North pole. Find the weight of this same person at the equator. (You don't need to use
Newton's Law of Gravitation but you do need to analyze the radial/centripetal force.)
person at the North pole. Find the weight of this same person at the equator. (You don't need to use
Newton's Law of Gravitation but you do need to analyze the radial/centripetal force.)
Answers
Elena
Weight(pole) = mg,
Weight (equator) =mg - F(centripetal)=mg - mv²/R
Weight (equator) =mg - F(centripetal)=mg - mv²/R