Asked by Alyonka

The bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 mph faster than the other, what was the speed of each bicyclist?

So far these are the equations I have gotten:

Distance1 + Distance2= 300miles
rate1(time1) + rate2(time2)= 300 miles
rate1= rate2 + 20 mph
time1 + time2 = 6 hrs

However I cant combine them into one equation...

How would you do that
Answered by Henry
X mi/h = Speed of #1.
(X+20) mi/h = Speed of #2.

d1 + d2 = 300 Miles.
6x + 6(x+20) = 300
6x + 6x+ 120 = 300
12x = 300 - 120 = 180
X = 15 mi/h.
X+20 = 15 + 20 = 35 mi/h.

Answered by Henry
NOTE: Each rider was on the road 6 hrs.
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