Question

Can someone please tell me if I did this correctly?


Calculate the molarity of the HCl from the volumes of acid and base and the molarity of the NaOH. Use the following equation:

(molarity of acid)x(volume of acid)=(molarity of base)x(volume of added base)

equivalance point=number of mL of base to an acid

1mL=0.001L

HCl volume=25 mL=0.025L
NaOH=67.05mL=0.06705L

Molarity=Moles of solute
---------------
Liters of a solution

M=0.015000 moles of NaOH
----------------------
0.06705L

M=0.223713647M of NaOH

M1V1=M2V2

M1=M2V2
----
V1

M1=0.223713647M of NaOH * 0.06705L
---------
0.025L

M1= 0.600000001 M of HCl

0.600000001 M of HCl * 0.025L=
0.223713647 M of NaOH * 0.06705L

Answer 1

Brad, I tried to help yesterday by pointing out that these boards don't allow spacing; therfore, trying to draw division lines to show division is useless. If you want to divide a by b, you do it a/b = ?? and put parentheses around those parts that are together to avoid confusion. Also, I suggested you type the problem but I still don't see that. I see volume of both acid and base clear enough but I don't see a molarity, at least not one labeled molarity.
If you will type in L NaOH, L HCl, and molarity of one or the other we can help you.

Answer 2

Calculate the molarity of the HCl from the volumes of acid and base at equivalence point and the molarity of the NaOH.

L HCl=0.025
L NaOH=0.06705

NaOH moles M=0.015000

Answer 3

Does this help?

Calculate the molarity of the HCl from the volumes of acid and base and the molarity of the NaOH.

L HCl=0.025
L NaOH=0.06705

NaOH M=0.015000

Answer 4

Yes, very much, and thank you. I'm sorry to have taken so long to answer but I'm up to my neck in income tax time and some of my columns don't balance so.....
Here is the problem. Do it one of two ways, which ever is the easiest for you to do.
mols NaOH = L x M = 0.06705 L x 0.01500 = 0.00100575.
mols HCl = the same thing of 0.0010125.
The Molarity HCl = mols HCl/L HCl = 0.00100575/0.025 = 0.04023 M HCl.

The other way is to use the formula you were using.
M1V2 = M2V2 OR
M_HClV_HCl = M_NaOHV_NaOH.
M_HCl*0.025 = 0.01500*0.06705
Solve for M_HCl = 0.04023
Check my work. It's late and past my bed time.

Answer 5

You can see I made a typo in the post but I corrected it later.
mols NaOH = L x M = 0.06705 L x 0.01500 = 0.00100575.<b>This is correct</b>
mols HCl = the same thing of 0.0010125 <b>This should read the same thing of 0.00100575</b>.
The Molarity HCl = mols HCl/L HCl = 0.00100575/0.025 = 0.04023 M HCl.
<b> The answer is correct.</b>

Answer 6

Thank-you for your help. I did it the second way. The mistake I did make was that I divided when I should have multiplied. I appreciate your help in helping me find my error.