Asked by kkpdiluvu

A uniform electric field is directed upward and has a magnitude of 5 N/C. What are the magnitude and direction of the force on a charge of -3 C placed in this field?
F=Eq
E=5
q=-3
5(-3)=-15N Downward
Ok I have the downward correct the -15 is incorrect. Did I use the wrong equation?
Answered by drwls
Your F = E q formula is correct. Are you sure the charge was 3 Coulombs and not 3 microcoulombs (3 uC) ?
Answered by kkpdiluvu
I'm sure... I copy/paste this question on here to be sure I got it right.
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