Asked by Anna
Divide and check:
(3x^2-2x-13)divided by (x-2)
(3x^2-2x-13)divided by (x-2)
Answers
Answered by
Henry
(3x^2 - 2x - 13) / (x-2) = (3x + 4),
-5 Remainder.
Long division was used, but it is difficult to show here.
Check:
(x-2)(3x+4) =
3x^2 + 4x -6x - 8 =
(3x^2 - 2x -8) -5 = 3x^2 - 2x - 13.
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