Asked by Destini
A team has won 60% of the games it has played so far. If the team wins the 15 remaining games in the season, it will have won 80% of the season's games. How many games will the team play over the entire season?
Answers
Answered by
Henry
X = # of games so far.
X+15 = Total @ of games played.
Gw = 0.6x + 15 = Total games won.
Gp = X + 15 = Total games played.
Gw/Gp = (0.6x+15) / (X+15) = 0.80.
Cross multiply:
0.8x + 12 = 0.6x + 15
0.8x - 0.6x = 15 - 12
0.2x = 3
X = 15 Games.
Gp = X + 15 = 15 + 15 = 30 Games.
X+15 = Total @ of games played.
Gw = 0.6x + 15 = Total games won.
Gp = X + 15 = Total games played.
Gw/Gp = (0.6x+15) / (X+15) = 0.80.
Cross multiply:
0.8x + 12 = 0.6x + 15
0.8x - 0.6x = 15 - 12
0.2x = 3
X = 15 Games.
Gp = X + 15 = 15 + 15 = 30 Games.
Answered by
Anonymous
Let the number of played games in the first place be x. Total number of games is therefore x+15. Then 0.6x games were won in the first place. If the extra 15 will be won, then total games won is 0.6x+15=0.8(x+15). Solving this equation. Then solve for x in this equation. The final answer is therefore the value x add 15 (q.e.d)
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