Did you intend to type kJ/g instead of K/g? And I assume the hydrocarbon warmed the water because it was burned.
q heat released = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q/2.00 = J/gram. Convert to kJ/g.
2.00 grams of hydrocarbon warmed 150.0 ml. water from 25.0 degree C to 30.0 degree C. Calculate the heat of hydrocarbon in K/g. the specific heat of water is 4.184 J/g. degree C
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