Asked by najuma
you sample 100 women and the average mean is 16, Calculate 95% Confidence interval for the sample. Do you have evidence the true mean is not 14? i need help please
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Answered by
najuma
you sample 100 women and the average mean is 16, Calculate 95% Confidence interval for the sample. Do you have evidence the true mean is not 14? i need help please, Standard D is 1
Answered by
PsyDAG
Z = (mean1 - mean2)/standard error (SE) of difference between mean
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√n
If only one SD is provided, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score. Is it less than you alpha error (P ≤ .05)?
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√n
If only one SD is provided, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score. Is it less than you alpha error (P ≤ .05)?