Asked by lindsay
Solve the equation
3^2x - 12 x 3^x + 27 = 0
3^2x - 12 x 3^x + 27 = 0
Answers
Answered by
Reiny
let 3^x = y
so we get
y^2 - 12y + 27 = 0
(y-3)(y-9) = 0
y = 3 or y = 9
then
x^2 = 3 or x^2 = 9
x = ± √3 or x = ± 3
btw, in something like 12 x 3^x , do not use x as a multiplication sign, especially if you have a variable x
either say just 12(3^x) or say 12*3^x
so we get
y^2 - 12y + 27 = 0
(y-3)(y-9) = 0
y = 3 or y = 9
then
x^2 = 3 or x^2 = 9
x = ± √3 or x = ± 3
btw, in something like 12 x 3^x , do not use x as a multiplication sign, especially if you have a variable x
either say just 12(3^x) or say 12*3^x
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