Asked by cathy
update yes, sorry I wrote it wrong
(mx)= (x^5-5x^3 +7x-4)^10 * (4x^9 +19)^23
Thanks again
(mx)= (x^5-5x^3 +7x-4)^10 * (4x^9 +19)^23
Thanks again
Answers
Answered by
Reiny
m'(x)= (x^5-5x^3+7x-4)^10 * 23(4x^9+19)^22 *(36x^8) + (4x^9+19^23 * 10(x^5-5x^3+7x-4)^9 * (5x^4 - 15x^2 +7)
etc
I can see some factoring if needed
check my arithmetic
BTW, try to stay within a thread of a question, don't start a new post for the same question.
I was expecting your reply in your previous post
etc
I can see some factoring if needed
check my arithmetic
BTW, try to stay within a thread of a question, don't start a new post for the same question.
I was expecting your reply in your previous post
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