A 1.90-g sample of a large biomolecule was dissolved in 25.0 g of carbon tetrachloride. The boiling point of this solution was determined to be 77.85°C. Calculate the molar mass of the biomolecule. For carbon tetrachloride, the boiling point constant is 5.03°C · kg/mol, and the boiling point of pure carbon tetrachloride is 76.50°C.

1 answer

delta T = Kb*m
delta T = 77.85-76.50
Kb = 5.03
Solve for m
m = mols/kg solvent. You know m and kg solvent, solve for mols.
mol = grams/molar mass. You know mol and grams, solve for molar mass.