The north-south component of the displacement is
Y = -5 -8 cos 45 = -10.65 km
The west-east component of the displacement is
X = -3 +8 cos45 = 2.657 km
Final displacement = sqrt[(10.65)^2 + 2.657^2] = 10.976 km
Bearing = tan^-1 2.657/10.65
= 14 degrees S of E
= 104 clockwise from north
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a cross country runner runs 3km due east, 5km due south and 8km south west. what is the runners final displacement and what direction in true bearing form?
PLEASE CAN YOU EXPLAIN IT STEP BY STEP
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