Asked by Tap
PLEASE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!
a cross country runner runs 3km due east, 5km due south and 8km south west. what is the runners final displacement and what direction in true bearing form?
PLEASE CAN YOU EXPLAIN IT STEP BY STEP
a cross country runner runs 3km due east, 5km due south and 8km south west. what is the runners final displacement and what direction in true bearing form?
PLEASE CAN YOU EXPLAIN IT STEP BY STEP
Answers
Answered by
drwls
The north-south component of the displacement is
Y = -5 -8 cos 45 = -10.65 km
The west-east component of the displacement is
X = -3 +8 cos45 = 2.657 km
Final displacement = sqrt[(10.65)^2 + 2.657^2] = 10.976 km
Bearing = tan^-1 2.657/10.65
= 14 degrees S of E
= 104 clockwise from north
Y = -5 -8 cos 45 = -10.65 km
The west-east component of the displacement is
X = -3 +8 cos45 = 2.657 km
Final displacement = sqrt[(10.65)^2 + 2.657^2] = 10.976 km
Bearing = tan^-1 2.657/10.65
= 14 degrees S of E
= 104 clockwise from north
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.