Asked by Beth
suppose that the angle of incidence is 1 = 37.1°, the thickness of the pane is 4.17 mm, and the refractive index of the pane is n2 = 1.50. Find the amount (in mm) by which the emergent ray is displaced relative to the incident ray.
Answers
Answered by
drwls
Refer to the figure at
http://img361.imageshack.us/img361/773/displacementduetorefracra3.gif
Use the formula derived at
http://www.kwantlen.bc.ca/science/physics/faculty/mcoombes/P1102_Solutions/Refraction/P1102_01_Solutions.htm
but use the appropriate values of the incidence angle, refractive index and the thickness.
http://img361.imageshack.us/img361/773/displacementduetorefracra3.gif
Use the formula derived at
http://www.kwantlen.bc.ca/science/physics/faculty/mcoombes/P1102_Solutions/Refraction/P1102_01_Solutions.htm
but use the appropriate values of the incidence angle, refractive index and the thickness.
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