Asked by Anonymous

What is the derivative of y = square root of 3x
Answered by Damon
y = (3x)^.5
dy/dx = .5 (3x)^-.5 * 3
dy/dx = 1.5/sqrt(3x)
Answered by Bosnian
y = sqrt ( 3 x ) = sqrt ( 3 ) * sqrt ( x )

d y / d x =sqrt ( 3 ) * 1 / 2 sqrt ( x )

d y / d x = ( 1 / 2 ) * sqrt ( 3 / x )
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