Asked by Q4
A person wajks on astraight road for 100 m and then return back for 20 m .The ratio of the magnitude of the distance to the displacement of the person is....
Answers
Answered by
Elena
Distance =100+20=120 m.
Displacement =100-20=80 m.
Distance/Displacement =120/80=1.5
Displacement =100-20=80 m.
Distance/Displacement =120/80=1.5
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