Asked by carolyn
sin t /1-cos t - 1+ cos t/sin t= 0
Answers
Answered by
Steve
sin t /(1-cos t) - (1+cos t)/sin t
sin t (1+cos t)/((1-cos t)(1+cos t)) - (1+cos t)/sin t
sin t (1+cos t)/(1-cos^2 t) - (1+cos t)/sin t
sin t (1+cos t)/sin^2 t - sin t (1+cos t)/sin^2 t
0
sin t (1+cos t)/((1-cos t)(1+cos t)) - (1+cos t)/sin t
sin t (1+cos t)/(1-cos^2 t) - (1+cos t)/sin t
sin t (1+cos t)/sin^2 t - sin t (1+cos t)/sin^2 t
0
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