Asked by Maihul
A car starts from rest and moves along x-axis with constant acceleration (5m/secondsquare) fr 8 sec. If it then countinues with constant velocity. What distance will the car cover in 12 sec since it started frm rest. plz anybody explain me
Answers
Answered by
bobpursley
Memorize this:
distance=initialvelocity*time+ 1/2 acceleration*time^2
distance=initialvelocity*time+ 1/2 acceleration*time^2
Answered by
Pawan
THE CAR COVERS 7.5M/SECONDSQUARE
Answered by
Khan
10
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