Asked by Anonymous
What is the diameter of a barrel that is 3.5 ft tall and holds 11 cubic feet of water
Answers
Answered by
Reiny
vol = πr^2 h
πr^2 (3.5) = 11
r^2 = 11/(3.5π)
r = √(11/(3.5π)) = appr 1
so the diameter is appr 2 ft
check:
Vol = π(1^2)(3.5) = 10.9955.. , OK!
πr^2 (3.5) = 11
r^2 = 11/(3.5π)
r = √(11/(3.5π)) = appr 1
so the diameter is appr 2 ft
check:
Vol = π(1^2)(3.5) = 10.9955.. , OK!
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