Check the problem and be careful with the caps. Na2PO4^2- doesn't exist. It could be Na2PO4^-. It might be Na2HPO4 and the equation would be
Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-
I need to derive a net ionic equation after balancing:
NA2PO4 (2-) +HI =?
what I have so far is
NA2Po4 +2HI = 2NAI +H3PO4
I can't get any farther but the answer is
HPO4 (2-) +H =H2PO4
can someone help me with the steps?
4 answers
you are right. It is Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-
Can you explain how to get this, though? any steps would be helpful.
HPO4^- + H^+ ==> H2PO4^-
Can you explain how to get this, though? any steps would be helpful.
I think I've got it by looking through the balanced equation. It is just hard to understand the NA repeated twice on the right side of the equation.
Na2HPO4 + HI ==> NaI + NaH2PO4.
This is a double displacement (double replacement) reaction.
One Na on Na2HPO4 changes places with the H of HI. That's all that happens. So Na2HPO4 becomes NaH2PO4 and the HI becomes NaI.
This is a double displacement (double replacement) reaction.
One Na on Na2HPO4 changes places with the H of HI. That's all that happens. So Na2HPO4 becomes NaH2PO4 and the HI becomes NaI.
1 answer