Asked by Nancy

I need to derive a net ionic equation after balancing:

NA2PO4 (2-) +HI =?
what I have so far is
NA2Po4 +2HI = 2NAI +H3PO4
I can't get any farther but the answer is
HPO4 (2-) +H =H2PO4

can someone help me with the steps?
Answered by DrBob222
Check the problem and be careful with the caps. Na2PO4^2- doesn't exist. It could be Na2PO4^-. It might be Na2HPO4 and the equation would be
Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-
Answered by Nancy
you are right. It is Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-

Can you explain how to get this, though? any steps would be helpful.
Answered by Nancy
I think I've got it by looking through the balanced equation. It is just hard to understand the NA repeated twice on the right side of the equation.
Answered by DrBob222
Na2HPO4 + HI ==> NaI + NaH2PO4.

This is a double displacement (double replacement) reaction.
One Na on Na2HPO4 changes places with the H of HI. That's all that happens. So Na2HPO4 becomes NaH2PO4 and the HI becomes NaI.
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