Question

A .035-kg bullet is fired vertically at 180 m/s into a .15-kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collicion, assuming the bullet embeds itself in the ball? Answer in meters.
initial momentum = .035*180 = 6.3 kg m/s
new mass = .035+.15 = .185 kg
new momentum = old momentum
6.3 = .185 v
v = 34.05 m/s
Ke = (1/2) m v^2 = (1/2)(.185)(34.05)^2
= 107.3 Joules
m g h = 107.3
h = 59.1

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