How much is the acceleration? Not stated in the problem!
anyway, you can use the formula:
V^2 = U^2 + 2*a*s
here a = accleration, U=0 and s = 2-1= 1m
anyway, you can use the formula:
V^2 = U^2 + 2*a*s
here a = accleration, U=0 and s = 2-1= 1m
The given acceleration of the particle is a = 4 m/s^2, and we need to find the velocity of the particle at s = 2m.
We are also given that the particle starts from rest when s = 1m. This means that initially, the particle has zero velocity (u = 0 m/s) at s = 1m.
Let's use the following equation of motion to solve for the final velocity:
v^2 = u^2 + 2as
where:
v = final velocity when s = 2m (what we want to find)
u = initial velocity (0 m/s)
a = acceleration (4 m/s^2)
s = displacement (2m - 1m = 1m)
Plugging in the values into the equation, we have:
v^2 = 0^2 + 2 * 4 * 1
v^2 = 0 + 8
v^2 = 8
To find the velocity, we take the square root of both sides of the equation:
v = √8
Calculating the square root of 8, we get:
v ≈ 2.83 m/s
Therefore, the particle's velocity when s = 2m is approximately 2.83 m/s.