Ask a New Question

Asked by Sierra

A jogger is running around a circular track of circumference 480 m. If the jogger has a speed of 11 km/h, what is the magnitude of the centripetal acceleration of the jogger?
13 years ago

Answers

Answered by Elena

2πR=480 m
R=480/2π =76.4 m
v=11 km/h =11000/3600 =3.06 m/s.
a(centr)=v²/R= 3.06²/76.4 =0.12 m/s²
13 years ago

Related Questions

A jogger follows this route every morning. Assume each segment is a straight line. A= 1000m due s... After 10.3 s, a jogger’s displacement is 360 m. What is the average velocity in m/s? Answer in units... A jogger takes the following route to the entrance of their local park: north 50 m, west 50 m, sout... A jogger is moving at 5 m/s as she approaches a busy street. She needs to stop in 2 seconds in order... A jogger with a mass of 66.0 kg reaches the top of a staircase in 44.0 s. If the distance from the b... a jogger with a mass of 60.0kg is moving at a speed of 3.0m/s. what is the jogger's kinetic energy?... A jogger is running around a 3/4 mile track and is 2/3 around the track. How far has the jogger trav... A 54-kg jogger is running at a rate of 3m/s. What is the kinetic energy of the jogger. A. 18 Jou... A jogger goes 1.5km and then turns north. If the jogger finishes 1.7km from the starting​ point, how... the jogger has already burned 225 calories today and is burning calories at the rate of 250 per hour...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use