Asked by Sierra
                A jogger is running around a circular track of circumference 480 m. If the jogger has a speed of 11 km/h, what is the magnitude of the centripetal acceleration of the jogger?
            
            
        Answers
                    Answered by
            Elena
            
    2πR=480 m
R=480/2π =76.4 m
v=11 km/h =11000/3600 =3.06 m/s.
a(centr)=v²/R= 3.06²/76.4 =0.12 m/s²
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.