Asked by Anonymous
How much bigger is the area of a square with side 3x + 2y inches than a square with side 2x - y inches?
Answers
Answered by
Reiny
Area of square with side 3x+2y
= (3x+2y)^2
= 9x^2 + 12xy + 4y^2
area of square with side 3x-2y
= (3x-2y)^2
= 9x^2 - 12xy + 4y^2
difference = 24xy
= (3x+2y)^2
= 9x^2 + 12xy + 4y^2
area of square with side 3x-2y
= (3x-2y)^2
= 9x^2 - 12xy + 4y^2
difference = 24xy
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