!!! The last words in given data have to be
“and 3 times as tall”
If so, then:
f = focal length of lens = 10cm
di = image distance from lens
do= object distance M =3 - magnification
Note that for the image to be upright it must be a virtual image, so di is negative.
di/do = -3
so di = -3do
1/10 = 1/do + 1/di
1/10 = 1/do - 1/(3•do) = 2/3•do
3•do = 20
do = 6.67cm
at what distance would a convex magnifing lens that has a focal length of 10 cm have to be held for an image to appear upright and 3 cm tall?
[6.67cm]
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