Asked by paukate08
a gardener is planning to make a rectangular garden with an area of 80ft^2.she has 12 yards of fencing to put around the perimeter of the garden.what should the dimension of the garden be ?
Answers
Answered by
Reiny
For a given perimeter, that largest area area of a rectangle is obtained when the rectangle is a square.
so if each side is x ft
x^2 = 80
x = √80 = 4√5
She needs 16√5 ft or appr 35.8 ft of fencing.
With only 12 feet she cannot have a rectangular field of 80 ft
or
with 12 ft of fencing , she can build a 3by3 square which will hold 9 square ft, not the 80 she wants.
Your question is flawed.
so if each side is x ft
x^2 = 80
x = √80 = 4√5
She needs 16√5 ft or appr 35.8 ft of fencing.
With only 12 feet she cannot have a rectangular field of 80 ft
or
with 12 ft of fencing , she can build a 3by3 square which will hold 9 square ft, not the 80 she wants.
Your question is flawed.
Answered by
Steve
She has 12 <b>yards</b>, or 36 feet of fencing.
That will enclose 9x9 = 81 ft^2, so by moving away from a square, she can use the whole 36 ft to enclose only 80 ft^2.
80 = 16*5 = 4*(4*5) so if the garden is 8x10 feet, its perimeter is 36 and its area is 80
That will enclose 9x9 = 81 ft^2, so by moving away from a square, she can use the whole 36 ft to enclose only 80 ft^2.
80 = 16*5 = 4*(4*5) so if the garden is 8x10 feet, its perimeter is 36 and its area is 80
Answered by
Reiny
I violated one of the first rules I taught my students years ago ...
Read the question carefully, and read it more than once.
Read the question carefully, and read it more than once.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.